二进制运算 逻辑运算
进制转换
原码补码反码
(1) (111000)2=( )16

(2) 43H= D
(3) (5324)10=( )16

(4)下列4种不同数制表示的数中,数值最小的一个
A)八进制数52 B)十进制数44
C)十六进制数2B D)二进制数101001

(5) 110110B = D
(6)234D = B
(7) (EF)16 = ( )2
(8) (76)8= ( )2
(9) (1010101101)2=( )16
(10) (23.625)10 = ( )2
(1) 1011 ∧ 1001 =
(2) 10101 ∨ 11100 =
(3)101 =
(4) 100 ∧ 111 =
(5)1011 1001 =
(6)1001 ∨ 1011 =
(7) 10010 ∧ 10110 =
(8)1101 1011 =
(9)1000 ∧ 1101 =
(10)1111 ∨ 1011=
(1)(1011)2+(10010)2 =
(2)(100101)2-(11100)2 =
(3)(11001)2×(111)2 =
(4)(100011)2÷(111)2 =
(5)(100010)2÷(1001)2 =
(6)(10101)2+(1011)2 =
(7)(101100)2-(10110)2 =
(8)(11010)2×(1011)2 =
(9)(1000001)2÷(1101)2 =
(10)(1111)2×(111)2 =
设字长= 8,求下列10进制数的原码,反码,补码:
31 -41 -19
(2) 求10进制数-20.125的二进制浮点数(1B存储阶码,3B存储尾数)).